Y^2+2xy+3x^2=10

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Solution for Y^2+2xy+3x^2=10 equation: 


Simplifying
Y2 + 2xy + 3x2 = 10

Solving
Y2 + 2xy + 3x2 = 10

Solving for variable 'Y'.

Move all terms containing Y to the left, all other terms to the right.

Add '-2xy' to each side of the equation.
Y2 + 2xy + -2xy + 3x2 = 10 + -2xy

Combine like terms: 2xy + -2xy = 0
Y2 + 0 + 3x2 = 10 + -2xy
Y2 + 3x2 = 10 + -2xy

Add '-3x2' to each side of the equation.
Y2 + 3x2 + -3x2 = 10 + -2xy + -3x2

Combine like terms: 3x2 + -3x2 = 0
Y2 + 0 = 10 + -2xy + -3x2
Y2 = 10 + -2xy + -3x2

Simplifying
Y2 = 10 + -2xy + -3x2

Reorder the terms:
-10 + Y2 + 2xy + 3x2 = 10 + -2xy + -3x2 + -10 + 2xy + 3x2

Reorder the terms:
-10 + Y2 + 2xy + 3x2 = 10 + -10 + -2xy + 2xy + -3x2 + 3x2

Combine like terms: 10 + -10 = 0
-10 + Y2 + 2xy + 3x2 = 0 + -2xy + 2xy + -3x2 + 3x2
-10 + Y2 + 2xy + 3x2 = -2xy + 2xy + -3x2 + 3x2

Combine like terms: -2xy + 2xy = 0
-10 + Y2 + 2xy + 3x2 = 0 + -3x2 + 3x2
-10 + Y2 + 2xy + 3x2 = -3x2 + 3x2

Combine like terms: -3x2 + 3x2 = 0
-10 + Y2 + 2xy + 3x2 = 0

The solution to this equation could not be determined.

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